4.9t^2+4t-350=0

Solution for 4.9t^2+4t-350=0 equation:

4.9t^2+4t-350=0

a = 4.9; b = 4; c = -350;
Δ = b2-4ac
Δ = 42-4·4.9·(-350)
Δ = 6876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6876}=\sqrt{4*1719}=\sqrt{4}*\sqrt{1719}=2\sqrt{1719}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{1719}}{2*4.9}=\frac{-4-2\sqrt{1719}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{1719}}{2*4.9}=\frac{-4+2\sqrt{1719}}{9.8}
$